256+-32x+x^2=202

Solution for 256+-32x+x^2=202 equation:

256+-32x+x^2=202

We move all terms to the left:

256+-32x+x^2-(202)=0

determiningTheFunctionDomain
x^2-32x+256-202+=0

We add all the numbers together, and all the variables

x^2-32x=0

a = 1; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·1·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*1}=\frac{64}{2}
=32
$